In this task, the Confidence interval used; 95% or 99% which are common. Here are the already known Z values for some of the common Confidence intervals and the CIs results;
|
C I of Difference using z-scores |
|||
|
CL |
90% |
upper |
0.201 |
|
z |
1.645 |
Lower |
-3.001 |
|
CL |
95% |
upper |
0.508 |
|
z |
1.96 |
Lower |
-3.308 |
|
CL |
99% |
upper |
1.107 |
|
z |
2.576 |
Lower |
-3.907 |
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Other additional results include;
|
Two Population (mean) Statistics |
||
|
First Sample |
Mean 1 |
80.4 |
|
First Sample |
Size 1 |
108 |
|
Second Sample |
Mean 2 |
81.8 |
|
Second Sample |
Size 2 |
92 |
|
Difference |
Mean Diff |
-1.4 |
|
Sample Standard Deviation 1 |
Stdev. 1 |
6.70567 |
|
Sample Standard Deviation 2 |
Stdev. 2 |
6.989041 |
|
Standard Error of Statistic |
SE |
0.97329 |
The mean difference at 95% and 99% CI is -1.4.
Therefore, the 95% CI is
While, the 99% CI is
This indicates that, the mean number of times that male experience heart diseases is from -3.907 to 1.107 times.
However, the "95%" conclude that 95% of the mean number of times that male experience heart diseases will include the true mean, but 5% won't.
Therefore, there is a 1-in-20 chance (5%) that the calculated Confidence Interval does NOT include the true mean.
