Question. Go to a local library; collect a sample of books consisting of the ages of book (based on copyright dates). Plan and describe the sampling procedure, then use the results to construct a confidence interval estimate of the mean age of all books in the library. Please, post and share your results with the class. the mean and the standard deviation obtained from the library and test the claim that the mean age of all books in the library is greater than 2005. Share your results as well.
My sample based on the copyright dates is as follows:
Year Age
2014 24
2013 23
2004 14
2002 12
1999 9
1992 2
Total 84
84/6 = 14
= 2004
Basing on these dates, the mean date for the sample of the books is 2004.
Standard Deviation
24 - 14 = 10
10^2 = 100
23-14 = 9
9^2 = 81
0
12 - 14 = -2
(-2)^2 = 4
9-12 = -3
(-3)^2 = 9
2-14 = -12
(-12)^2 = 144
100, 81, 0, 4, 9, 144 = 338/6
= 56.33
square root = 7.51
Standard deviation becomes 7.51
Mean ± Z SEm
SEm = SD/ √ n
7.51/ 2.45 = 3.07
3.07 x 0.025 = 0.08 + 14 = 14.08
Answer = 95%
Delegate your assignment to our experts and they will do the rest.
