This solution is for OPTION 1
Step 1
This is involving identification of the number of observations; n thereafter calculating its mean score; X-bar and finally, the standard deviation is also calculated; s.
In Option 1;
Number of observations; n = 7
The mean is given by;
The standard deviation; s is calculated as follows;
Step 2
Here, involve deciding on which Confidence interval to use; 95% or 99% which are common. In this case, I have decided to use the 95% confidence interval. Here are the already known Z values for some of the common Confidence intervals;
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Confidence Interval | Z |
90% |
1.645 |
95% |
1.96 |
99% |
2.576 |
99.90% |
2.807 |
Step 3
This will involve using the Z value above to calculate the confidence interval whose formula is given as;
Where:
X is the mean
Z is the chosen Z-value from the table above
s is the standard deviation
n is the number of observations
Therefore, we have,
This indicates that, the mean number of times that adults go out for dinner each week is from -0.5259 to 4.1854 times.
However, the "95%" conclude that 95% of the mean number of times that adults go out for dinner each week will include the true mean, but 5% won't, ( Salkind, 2016) .
Therefore, there is a 1-in-20 chance (5%) that the calculated Confidence Interval does NOT include the true mean.
References
Salkind, N. J. (2016). Statistics for people who (think they) hate statistics . Sage Publications.