16 Dec 2022

60

Manager of a Bottling Company

Format: APA

Academic level: College

Paper type: Essay (Any Type)

Words: 635

Pages: 2

Downloads: 0

Background 

As a manager of a bottling company, the claim is that the company’s product (bottled sodas) weighs 16 ounces. The customers however, have complained that the company’s bottled soda does not weigh 16 ounces but instead weighs less than the company’s claim. The boss of the company called for an investigation into this matter and a random sample of 30 bottles from all the shifts of the bottling plant was selected. The weight of the randomly selected bottled sodas was measured and statistical analyses were performed as discussed in the following steps. 

Mean, median and standard deviation 

The mean, median and the standard deviation for the ounces measured for the 30 randomly selected bottles was calculated using excel and the following results were obtained. 

It’s time to jumpstart your paper!

Delegate your assignment to our experts and they will do the rest.

Get custom essay
Column1 
  
Mean 

15.854 

Standard Error 

0.120751098 

Median 

15.99 

Mode 

16.21 

Standard Deviation 

0.661381 

Sample Variance 

0.437424828 

Kurtosis 

0.559167406 

Skewness 

-0.792894156 

Range 

2.73 

Minimum 

14.23 

Maximum 

16.96 

Sum 

475.62 

Count 

30 

Explanation 

From the above table obtained from excel, the mean of the 30 bottled sodas was found to be 15.854 ounces and a standard deviation of 0.661381. This means that on average the weight of a randomly selected bottle will be 15.85 ounces or approximately 16 ounces when rounded off to the nearest whole number. The standard deviation is the square root of the variance and it shows how much different weights vary from the mean. In this case, the bottled sodas weight deviates by 0.66 ounces from the mean weight. The calculated median value was found to be 15.99 and the mode which shows the most repeated weight value was found to be 16.21. 

A 95% Confidence Interval for the ounces in the bottles. 

The confidence interval is a range of values in which the true value of a population parameter lies. The company was interested in finding the 95% confidence level of the weights of the selected products and the analysis was conducted using excel software to obtain the following results. 

Column1 
  
Mean 

15.854 

Standard Error 

0.120751098 

Median 

15.99 

Mode 

16.21 

Standard Deviation 

0.661381 

Sample Variance 

0.437424828 

Kurtosis 

0.559167406 

Skewness 

-0.792894156 

Range 

2.73 

Minimum 

14.23 

Maximum 

16.96 

Sum 

475.62 

Count 

30 

Confidence Level (95.0%) 

0.246963724 

The 95% confidence level value was obtained as 0.24696. The confidence interval is given by [15.607 < 15.854 < 16.101] i.e. (15.854-0.24696 = 15.60703628) and (15.854+0.24696= 16.10096372). This implies that the company can be 95% confident that the weight of their bottled soda is between 15.6 ounces and 16.1 ounces. Therefore, if more surveys are to be done in future, then 95% of them would result in confidence intervals that include the true population proportion. 

Hypothesis Test 

In order to test the claim made by the customers that the weight of the bottled sodas is less than 16 ounces, a hypothesis test was conducted. Since the data collected had a sample size of 30 and there was no population standard deviation given, a one sample t-test was conducted in order to test the claim that the weight is less than 16 ounces. The null and the alternative hypothesis were formulated as follows. 

H 0 : µ=16 

H 1 : µ<16 

The following one-sided t-test was obtained from excel. 

  
t-Test: one sample  
 Ounces 
Mean 

15.854 

Variance 

0.437424828 

Observations 

30 

Hypothesized Mean 

16 

df 

29 

t Stat 

-1.20909874 

P(T<=t) one-tail 

0.118195315 

t Critical one-tail 

1.699127027 

P(T<=t) two-tail 

0.23639063 

t Critical two-tail 

2.045229642 

Analysis 

The t statistic value obtained was -1.209 with a p value of 0.1182. The null hypothesis is only rejected when the t stat value is greater than the tabulated value but in this case, the t stat value is -1.209 and the tabulated value from the student t distribution table is 1.699. This implies that t calculated (-1.209) is less than t tabulated (1.699) therefore, the null hypothesis is not rejected. 

The null hypothesis therefore is true and the conclusion is that, the company’s claim that the weight of the bottled sodas has a mean weight of 16 ounces holds. In other words, it is true the product has a weight of 16 ounces as advertised and the customer’s complaints are not warranted. 

Recommendation 

From the statistical analysis conducted above, it is clear that the customer’s complaints are not justified. I would assume that the customers are made to believe that our products are less than what is advertised because of our packaging material. When comparing our bottled products to other companies, ours seem lighter due to our plastic packaging material. I would strongly suggest therefore, that we change our packaging material to cans or even glass bottles as they weigh slightly more than plastic. This, I believe, would restore our customer confidence. 

Illustration
Cite this page

Select style:

Reference

StudyBounty. (2023, September 14). Manager of a Bottling Company.
https://studybounty.com/manager-of-a-bottling-company-study-essay

illustration

Related essays

We post free essay examples for college on a regular basis. Stay in the know!

17 Sep 2023
Statistics

Scatter Diagram: How to Create a Scatter Plot in Excel

Trends in statistical data are interpreted using scatter diagrams. A scatter diagram presents each data point in two coordinates. The first point of data representation is done in correlation to the x-axis while the...

Words: 317

Pages: 2

Views: 186

17 Sep 2023
Statistics

Calculating and Reporting Healthcare Statistics

10\. The denominator is usually calculated using the formula: No. of available beds x No. of days 50 bed x 1 day =50 11\. Percentage Occupancy is calculated as: = =86.0% 12\. Percentage Occupancy is calculated...

Words: 133

Pages: 1

Views: 150

17 Sep 2023
Statistics

Survival Rate for COVID-19 Patients: A Comparative Analysis

Null: There is no difference in the survival rate of COVID-19 patients in tropical countries compared to temperate countries. Alternative: There is a difference in the survival rate of COVID-19 patients in tropical...

Words: 255

Pages: 1

Views: 250

17 Sep 2023
Statistics

5 Types of Regression Models You Should Know

Theobald et al. (2019) explore the appropriateness of various types of regression models. Despite the importance of regression in testing hypotheses, the authors were concerned that linear regression is used without...

Words: 543

Pages: 2

Views: 174

17 Sep 2023
Statistics

The Motion Picture Industry - A Comprehensive Overview

The motion picture industry is among some of the best performing industries in the country. Having over fifty major films produced each year with different performances, it is necessary to determine the success of a...

Words: 464

Pages: 2

Views: 86

17 Sep 2023
Statistics

Spearman's Rank Correlation Coefficient (Spearman's Rho)

The Spearman’s rank coefficient, sometimes called Spearman’s rho is widely used in statistics. It is a nonparametric concept used to measure statistical dependence between two variables. It employs the use of a...

Words: 590

Pages: 2

Views: 308

illustration

Running out of time?

Entrust your assignment to proficient writers and receive TOP-quality paper before the deadline is over.

Illustration