Question A
X |
Y |
XY |
X 2 |
|
30 |
12 |
360 |
900 |
|
40 |
20 |
800 |
1600 |
|
50 |
24 |
1200 |
2500 |
|
60 |
38 |
2280 |
3600 |
|
70 |
40 |
2800 |
4900 |
|
Sum |
250 |
134 |
7440 |
13500 |
62500 |
N=5 |
Question B
In this question we will use the z hypothesis test.
Since the alpha level is , the z critical value is
Therefore, because the z statistic is less than the critical value then we reject the null hypothesis and accept the alternate hypothesis and accept the population mean is greater than
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Question C
Assuming that the names of the groups are A, B, C and D. The hypotheses are as follows
Using Excel, I performed ANOVA analysis and found. The excel sheet is attached.
ANOVA | ||||||
Source of Variation |
SS |
df |
MS |
F |
P-value |
F critical |
Between Groups |
99.66666667 |
3 |
33.22222222 |
1.898412698 |
0.208346 |
4.066181 |
Within Groups |
140 |
8 |
17.5 |
|||
Total |
239.6666667 |
11 |
Conclusion
Since the p-value (0.208346) is not less than 0.05, we fail to reject the null hypothesis.
Question D
We know that
From the question therefore using normal approximation becomes
We also know that therefore we can determine the mean and the standard deviation.
The mean therefore is
We are asked to compute . To find this probability we need to find the z score
Therefore,
Using the z table we establish that the probability of being less than z score of is and the probability of being less than z score of is 0.6915.
To determine this . We do
Therefore
Question E
We are given
Therefore,
Using Z score table we find the probability that
Question F
We are given
Therefore,
For the z score , probability is and for z score is the probability is . Therefore, the probability that is which is 6.68% and the probability that is 30.85%.