#Independent samples
Family |
Diabetes Education |
control |
||
1 |
10 |
7 |
||
2 |
8 |
8 |
||
3 |
5 |
9 |
||
4 |
4 |
6 |
||
5 |
6 |
5 |
||
6 |
10 |
9 |
||
Mean |
7.167 |
7.333 |
||
Standard Deviation |
2.563 |
1.633 |
||
n(participants) |
6 |
6 |
||
Variance |
6.567 |
2.667 |
||
Mean - Mean |
-0.167 |
|||
A |
32.833 |
13.333 |
46.167 |
|
B |
10 |
|||
C |
12 |
|||
D |
36 |
|||
A divide B |
4.617 |
|||
C divided D |
0.333 |
|||
1.539 |
||||
1.241 |
||||
t-test independent means |
-0.135 |
#Question
Null hypothesis; mean of experiment = mean of control
Observed t-statistic from Excel = -0.134
Critical t-value for this research question = 2.228
Conclusion: from the data above, the t-statistic value does not lie between -2.228 and 2.228
Therefore, we fail to reject the null hypothesis.
#Dependent samples
Family | Group | Diagnoses in year 1 | Diagnose in year2 | Difference | (Difference)^2 | |
1 | Diabetes Education | 10 | 6 | -4 | 16 | |
2 | Diabetes Education | 8 | 5 | -3 | 9 | |
3 | Diabetes Education | 5 | 6 | 1 | 1 | |
4 | Diabetes Education | 4 | 4 | 0 | 0 | |
5 | Diabetes Education | 6 | 2 | -4 | 16 | |
6 | Diabetes Education | 10 | 3 | -7 | 49 | |
sum | 43 | 26 | -17 | 91 | ||
n | 6 | |||||
A | -17 | |||||
B | 546 | |||||
C | 289 | |||||
D | 5 | |||||
E | 51.4 | |||||
F | 7.169 | |||||
t-test | ||||||
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#Questions
Null hypothesis; Mean of year 1 = Mean of year
Observed t-statistic from the data above in Excel = -2.37
The critical t-value from this research = 2.015
Conclusion: since t-value(-2.37) does not lie between -2.015 and 2.015 we reject the null hypothesis