Resistivity rate of tungsten is given as 5.6 x 10^-8 ohm•m
Diameter of the wire is 0.1 mm
Length is given as is 1m
Total area of the wire is given by π r 2
Therefore: 22/7 * (5*10/100000) ^2
= 7.85* 10^-9 m 2
Resistance is attained by multiplying resistivity by length divide by area (resistivity* length/ area)
= 5.6 x 10^-8 * 1/ 7.85* 10^-9
=7.13
If 12 V is applied across a wire:
I = V/R
= 12/7.13
= 1.68 A
Power= V^2/R
= 144/7.13
=2.02 w
The largest possible resistance can be achieved by connecting all the wires in series. The same current will be flowing through each resistor when the wires are connected in series. Therefore, current will be in constant and the outcome will be more power.
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Resistance= 9 * 7.13
= 64.17
Power = V^2/R
= 144/64.17
= 2.24 w
The value of resistance will be least when the wires are connected in parallel. The wires which are resistors in this case will have equal voltage of the source being used, thus power will be shared which explains why it is less. The more the wires that will be added, the power will be shared among them thus reducing the flow of current.
Power will be equal to 9(V^2/R)
= 9 * 122/7.13
= 181.76 W
