Heating 1kg of water on an electric stove to boiling point with a temperature recording after every 30 seconds.
Results
| Time In Seconds | Temperature in K |
| 0 | 298 |
| 30 | 302 |
| 60 | 307 |
| 90 | 311 |
| 120 | 316 |
| 150 | 320 |
| 180 | 326 |
| 210 | 330 |
| 240 | 333 |
| 270 | 338 |
| 300 | 347 |
| 330 | 352 |
| 360 | 357 |
| 390 | 361 |
| 420 | 365 |
| 450 | 372 |
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Calculations
E= c ⋅ m ⋅ ΔT
E= 4.18kJ per kg per Kelvin ×1kg×(372-298)K
E=4.18×74
E=309.32 kilojoules
c ⋅ m ⋅ ΔT= P ⋅ Δt
4.18×1×74/450 = P
Therefore, P = 0.6874 kilojoules per second
P = 687.4 joules per second
P = 687.4 Watts
NB: The power of the electric stove equals to 687.4 Watts.
