Part I
Q1. Difficulties in concentration, remembering and paying attention.
Q2. Central nervous system/brain
Q3. Her recessive genes cannot make hydroxylase, responsible for breaking down phenylalanine.
Q4. Parents. Heterozygous for PKU gene or pq
Q5. Either pq or p2
Q6. q2
Part II- Hardy-Weinberg
Q1. Unless you know the population size it's difficult. There are additional aspects to consider before you finalize the equation.
Q2.Yes, they can. Frequency of dominant allele, recessive allele frequency, homozygous dominant frequency, heterozygotes frequency, and homozygous recessive frequency.
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Part III – Carriers
Q1. Take the square root of q2
Q2.
p + q = 1
p=1-q
Q3.
33/300,000=0.011%. So q is 300,000x0.011
=3300
Q4. Random allele frequency changes, natural selection, genetic drift, mutation, gene flow, and mating behavior.
Q5. They were right, that means that their reason was appropriate in this case
Q6.
Janes’s chances -2pq
Janes's husband chances- 2pq
Chances for a PKU child is 2pq x 2pq x 0.25 = 0.000108
Q7.
Amanda chances - 2pq
Amanda's husband-2pq
Chances for a PKU child is 2pq x 2pq x 0.25 = 0.000108